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4 June, 00:58

What is the sum of n natural numbers: 1+2 + ... + n?

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  1. 4 June, 04:33
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    S = 1/2 n (n+1)

    Step-by-step explanation:

    1 + 2 + 3 + ... + n

    Now write in reverse order:

    n + n-1 + n-2 + ... + 1

    Add together:

    n+1 + n+1 + n+1 + ... + n+1

    n (n+1)

    Since this is double the sum:

    S = 1/2 n (n+1)
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