After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually. Which function describes the value of the car after t years? C (t) = 28,000 (0.158) t C (t) = 28,000 (1.575) t C (t) = 28,000 (0.811) t C (t) = 28,000 (0.189) t

Answer: C (t) = 28000 (0.811) ^t

Step-by-step explanation:

it begins to depreciate at a rate of 18.9% annually. This means that the rate at which the value is decreasing is exponential. We would apply the formula for exponential growth which is expressed as

y = b (1 - r) ^ t

Where

y represents the value of the car after t years.

t represents the number of years.

b represents the initial value of the car.

r represents rate of depreciation.

From the information given,

P = 28000

r = 18.9% = 18.9/100 = 0.189

Therefore

y = 28000 (1 - 0.189) ^t

y = 28000 (0.811) ^t

Where C (t) represents y, the function becomes

C (t) = 28000 (0.811) ^t