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9 October, 02:50

After a new $28,000 car is driven off the lot, it begins to depreciate at a rate of 18.9% annually. Which function describes the value of the car after t years? C (t) = 28,000 (0.158) t C (t) = 28,000 (1.575) t C (t) = 28,000 (0.811) t C (t) = 28,000 (0.189) t

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  1. 9 October, 06:18
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    Answer: C (t) = 28000 (0.811) ^t

    Step-by-step explanation:

    it begins to depreciate at a rate of 18.9% annually. This means that the rate at which the value is decreasing is exponential. We would apply the formula for exponential growth which is expressed as

    y = b (1 - r) ^ t

    Where

    y represents the value of the car after t years.

    t represents the number of years.

    b represents the initial value of the car.

    r represents rate of depreciation.

    From the information given,

    P = 28000

    r = 18.9% = 18.9/100 = 0.189

    Therefore

    y = 28000 (1 - 0.189) ^t

    y = 28000 (0.811) ^t

    Where C (t) represents y, the function becomes

    C (t) = 28000 (0.811) ^t
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