An object is thrown upward from a height of 192 feet with an initial velocity of 64 feet per second. The height h (in feet) of the object after t seconds is modeled by the equation

h=16t^2 + 64t+192.

How long will it take for the object to reach the ground?

in steps

Step-by-step explanation:

ground height = 0

(are you sure your formula is correct? isn't it - 16t²?)

if h=16t² + 64t+192 is true then

16t² + 64t+192 = 0

t² + 4t + 12 = 0

t = (-4 ± √ (4² - 4*12)) / 2*1 = (-4 ± √-32) / 2 = - 2 ± 2√-2

There is no solution of t

if it is h = - 16t² + 64t+192

0 = - 16t² + 64t + 192

t² - 4t - 12 = 0

(t + 2) (t - 6) = 0

t should be positive

t = 6 sec