The area of a rectangle is 42 square feet.

If the length and width are whole numbers, what are the least and greatest possible

perimeters?

26 ft. and 34 ft.

34 ft. and 86 ft.

26 ft. and 86 ft.

42 ft. and 84 ft.

Question

Mathematics

June

31 October, 02:33

The area of a rectangle is 42 square feet.

If the length and width are whole numbers, what are the least and greatest possible

perimeters?

26 ft. and 34 ft.

34 ft. and 86 ft.

26 ft. and 86 ft.

42 ft. and 84 ft.

+1

Answers (1)

Know the Answer?

Carley Harrell · Answer 1

26 ft and 46 ft.

Step-by-step explanation:

The prime factors of 42 are 2 * 3 * 7.

Possible lengths and widths are:

L = 7, W = 6 giving a perimeter of 2*7 + 2*6 = 26 ft.

L = 14, W = 3 giving perimeter = 34 ft.

L = 21, W = 2 giving perimeter = 46 ft.

The area of a rectangle is 42 square feet.If the length and width are whole numbers, what are the least and greatest possibleperimeters?26 ft. and 34 ft.34 ft. and 86 ft.26 ft. and 86 ft.42 ft. and 84 ft.

The area of a rectangle is 42 square feet.

If the length and width are whole numbers, what are the least and greatest possible

perimeters?

26 ft. and 34 ft.

34 ft. and 86 ft.

26 ft. and 86 ft.

42 ft. and 84 ft.