How can the sum of cubes, x^3 - 27, be written in factored form?

(x+3) (x^2+3x+9)

(x+3) (x^2-3x+9)

(x-3) (x^2+3x+9)

(x-3) (x^2-3x+9)

Question

Mathematics

Akira Conrad

28 April, 12:50

How can the sum of cubes, x^3 - 27, be written in factored form?

(x+3) (x^2+3x+9)

(x+3) (x^2-3x+9)

(x-3) (x^2+3x+9)

(x-3) (x^2-3x+9)

+1

Answers (1)

Know the Answer?

Anne · Answer 1

(x - 3) (x² + 3x + 9)

Step-by-step explanation:

The sum of cubes is factored as ...

... a³ + b³ = (a + b) (a² - ab + b²)

For a=x, b=-3, this is ...

... x³ - 27 = (x - 3) (x² + 3x + 9)

How can the sum of cubes, x^3 - 27, be written in factored form?(x+3) (x^2+3x+9)(x+3) (x^2-3x+9)(x-3) (x^2+3x+9)(x-3) (x^2-3x+9)

How can the sum of cubes, x^3 - 27, be written in factored form?

(x+3) (x^2+3x+9)

(x+3) (x^2-3x+9)

(x-3) (x^2+3x+9)

(x-3) (x^2-3x+9)