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20 June, 14:09

Which of the following shows the true solution to the logarithmic equation solved below?

log2 (x) + log2 (x + 7) = 3

log2[x (x+7) ] = 3

* (X + 7) - 23

x2 + 7x-8-0

(x+3) (x-1) = 0

X=-8,1

0

0

X=-8

X-1

x = 1 and x=-8

X = 1 and X = 8

+4
Answers (1)
  1. 20 June, 17:34
    0
    The answer is x=1
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