The difference of the square of a number and 28 is equal to three times the number find the negative solution

Answer:y=-4

Step-by-step explanation:

To find this

We get,

The difference between the square of the number

Let y be the unknown number

Square of y=y^2

Y^2-28=3y

Then let we are going to rearrange, then we get

y^2-3y-28

We are going to factorise

y^2-7y+4y-28

(y^2-7y + (4y-28)

y (y-7) + 4 (y-7) = 0

(y+4) (y-7) = 0

To find the negative number then we have

y=-4