An object is launched straight up into the air at an initial velocity of 64 feet per second it is launched from a height of 6 feet off the ground. Its height H, in feet, at seconds is given by the equation h = - 16t 2+64r + 6
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Home » Mathematics » An object is launched straight up into the air at an initial velocity of 64 feet per second it is launched from a height of 6 feet off the ground. Its height H, in feet, at seconds is given by the equation h = - 16t 2+64r + 6