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10 July, 04:06

If f (x) = - x - 2 and g (x) = x2, what is (gºf) (-6) ?

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  1. 10 July, 06:49
    0
    16

    Step-by-step explanation:

    (gºf) (x) involves using function f as the input to function g and is called a "composition."

    g (x) = x^2, so if we use f (x) = - x - 2 as input, we get

    (gºf) (x) = (-x - 2) ^2.

    At x = - 6, we have:

    (gºf) (-6) = (-[-6] - 2) ^2 = 4^2 = 16
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