A basket ball player makes 80% of his free throws. if he attempts two free throws, what are the chance that he miss both free throws

(options)

.4%

.6%

.8%

.12%

.20%

4%

Step-by-step explanation:

1) The player will miss 20% of their free throws.

2) That can be modeled by the fraction: 1/5.

3) Multiply 1/5 by 1/5 (he has a 1/5 chance of missing his shot for each shot so you multiply them together to get the probability of the player missing both).

4) 1/5 x 1/5 = 1/25

5) 1/25 can be modeled by the percent: 4%.