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22 March, 22:40

The floor of a shed given on the right has an area of 52 square feet. The floor is in the shape of a rectangle whose length is 5 feet less than twice the width. Find the length and the width of the floor of the shed.

Answers (1)
  1. J
    23 March, 01:33
    0
    13/2 feet width and 8 feet length

    Step-by-step explanation:

    We have that the area of a rectangle is as follows:

    ar = l * w

    we know that the value of the area is 52 ft ^ 2, therefore:

    l * w = 52

    According to the statement we have to:

    x = width

    2 * x - 5 = length

    we replace in the area formula and we have to:

    x * (2 * x - 5) = 52

    We solve and we are left with:

    2 * x ^ 2 - 5 * x - 52 = 0

    Factoring the above we are left with:

    (2 * x - 13) * (x + 4) = 0

    (x + 4) = 0, it means that x = - 4, a negative number, therefore this option cannot be.

    2 * x - 13 = 0

    x = 2/13, would be the width

    the length:

    2 * x - 5 = 2 * (2/13) - 5 = 8

    What the measurements mean is 13/2 feet width and 8 feet length
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