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23 January, 02:54

Find an equation in standard form for the hyperbola with vertices at (0, ±4) and foci at (0, ±5).

y squared over 16 minus x squared over 9 = 1

y squared over 25 minus x squared over 16 = 1

y squared over 16 minus x squared over 25 = 1

y squared over 9 minus x squared over 16 = 1

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  1. 23 January, 05:47
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    Answer:b

    Step-by-step explanation: Cause I took the test
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