A die is thrown 300 times with frequencies for the outcome 1 2 3 4 5 6, whats the probablity of getting a prime number, given the frequencies are 42 60 55 53 60 and 30 respectively?

58.3% to the nearest tenth.

Step-by-step explanation:

The prime numbers from 1 to 6 are 2,3 and 5.

The probability of a prime number taken from the result of the 300 throws:

= (sum of the frequencies for 2, 3 and 5) / (total throws)

= (60 + 55 + 60) / 300

= 0.5833 or 58.3%.