Which quadratic equation has two irrational roots?

O x2 + x + 3 = 0

O x² + 2x - 8=0

x² + 3x - 1=0

x2 - 2x + 1 = 0

x² + 3x - 1=0

Step-by-step explanation:

hello:

calculate : ∆ = b² - 4ac

x² + x + 3 = 0 : a = 1 b=1 c=3 ∆ = (1) ² - 4 (1) (3) = - 11 < 0 non reals roots

x² + 2x - 8=0 : a = 1 b=2 c=-8 ∆ = (2) ² - 4 (1) (-8) = 36 two rational roots

x² + 3x - 1=0 : a = 1 b=3 c=-1 ∆ = (3) ² - 4 (1) (-1) = 13 no perfect squard

so : two irrational roots?

x2 - 2x + 1 = 0 : (x-1) ²=0 one root