What is (x-2) ^2 + (y+1) ^2=4^2

Question

Mathematics

Nolan Atkins

12 January, 02:03

What is (x-2) ^2 + (y+1) ^2=4^2

+1

Answers (1)

Know the Answer?

Ryker Stephens · Answer 1

y = sqrt (16 - (x - 2) ^2) - 1 or y = - sqrt (16 - (x - 2) ^2) - 1

Step-by-step explanation:

Solve for y:

(x - 2) ^2 + (y + 1) ^2 = 16

Subtract (x - 2) ^2 from both sides:

(y + 1) ^2 = 16 - (x - 2) ^2

Take the square root of both sides:

y + 1 = sqrt (16 - (x - 2) ^2) or y + 1 = - sqrt (16 - (x - 2) ^2)

Subtract 1 from both sides:

y = sqrt (16 - (x - 2) ^2) - 1 or y + 1 = - sqrt (16 - (x - 2) ^2)

Subtract 1 from both sides:

Answer: y = sqrt (16 - (x - 2) ^2) - 1 or y = - sqrt (16 - (x - 2) ^2) - 1