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12 January, 02:03

What is (x-2) ^2 + (y+1) ^2=4^2

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Answers (1)
  1. 12 January, 04:13
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    y = sqrt (16 - (x - 2) ^2) - 1 or y = - sqrt (16 - (x - 2) ^2) - 1

    Step-by-step explanation:

    Solve for y:

    (x - 2) ^2 + (y + 1) ^2 = 16

    Subtract (x - 2) ^2 from both sides:

    (y + 1) ^2 = 16 - (x - 2) ^2

    Take the square root of both sides:

    y + 1 = sqrt (16 - (x - 2) ^2) or y + 1 = - sqrt (16 - (x - 2) ^2)

    Subtract 1 from both sides:

    y = sqrt (16 - (x - 2) ^2) - 1 or y + 1 = - sqrt (16 - (x - 2) ^2)

    Subtract 1 from both sides:

    Answer: y = sqrt (16 - (x - 2) ^2) - 1 or y = - sqrt (16 - (x - 2) ^2) - 1
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