A swimming pool in the shape of a right rectangular prism is filled with water. The pool is 25 yards long, 10 yards wide, and 2 feet deep. Water has an approximate density of 62.4 pounds per cubic foot. What is the weight of the water in the pool to the nearest pound? Enter the number only.

10400 lb

Step-by-step explanation:

First find the volume of the water in the pool: It is V = (length) (width) (height).

Here, V = (25 yds) (10 yds) (2/3 yd), or (500/3 yds³.

Then multiply this result by the unit rate (62.4 lb / ft³).

The result is 10400 lb. This is the weight of the water in the pool.