Ask Question
29 November, 00:13

How do i simplify: (sin pi/2 - x) / (cos pi/2 - x)

and

sec^2x-1 / secx-1

+3
Answers (1)
  1. 29 November, 00:44
    0
    tan (x) = sin (x) / cos (x)

    When x = pi/2-x, it's the same thing but you just substitute

    sin (pi/2-x) / cos (pi/2-x) = tan (pi/2-x)

    1/cos (x) = secx

    sec^2 (x-1) / sec (x-1) = sec (x-1) = 1/cos (x-1)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How do i simplify: (sin pi/2 - x) / (cos pi/2 - x) and sec^2x-1 / secx-1 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers