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15 July, 06:13

Four times a number was 22 greater than twice the same number. What was the number?

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Answers (2)
  1. 15 July, 08:26
    0
    Answer: 11

    Step-by-step explanation:

    Set up an equation

    Based on the question, we can determine that 4x = 22 + 2x where x in is the number

    "Four times a number" - > 4x

    "was" - > =

    "22 greater than" - > 22 +

    "twice the same number" - > 2x

    Put the underlined parts together to get 4x = 22 + 2x

    Solve equation

    Rearrange/collect like terms to solve for x by subtracting 2x from both sides

    4x = 22 + 2x

    2x = 22

    Solve for x by dividing each side by 2

    2x = 22

    x = 11

    Final Answer

    x = 11
  2. 15 July, 08:50
    0
    11

    Step-by-step explanation:

    let the number be x

    4x = 22+2x

    collect like terms

    4x - 2x = 22

    2x = 22

    divide both sides by the coefficient of x which is 2

    2x/2 = 22/2

    x = 11

    the number is 11
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