Kelly and Fawn both went to food land to buy eggs and bread. Kelly bought 3 dozen eggs and 5 loads of bread for $33. Fawn bought two dozen eggs and 2 loads of bread for $18. How much is each idem?

The answer to your question is below

Step-by-step explanation:

Data

Kelly bought 3 dozens of eggs and 5 loads of bread cost = $33

Fawn bought 2 dozens of eggs and 2 loads of bread cost = $18

Cost of each item = ?

Process

1. - Write one equation for Kelly and another for Fawn to solve this problem.

eggs = e

bread = b

3e + 5b = 33 Equation l

2e + 2b = 18 Equation ll

2. - Solve by elimination

- Multiply equation l by 2 and equation ll by - 3

6e + 10b = 66

-6e - 6b = -54

Simplify 0 + 4b = 12

-Solve for b b = 12/4

b = 3

3. - Substitute b in equation ll to find e

2e + 2 (3) = 18

2e + 6 = 18

2e = 18 - 6

2e = 12

e = 12/2

e = 6

4. - Conclusion

A dozen of eggs costs $6

A load of bread cost $3

Eggs are 6 dollars a dozen and bread is 3 dollars a loaf.

Step-by-step explanation:

Let the price of a dozen eggs be e dollars and the price of the bread be b dollars.

So we have the system:

3e + 5b = 33

2e + 2b = 18

We use the method of elimination:

Multiply the first equation by 2 and the second by - 5:

6e + 10b = 66

--10e - 10b = - 90 Adding:-

-4e = - 24

e = 6.

Substitute e = 6 in the first equation:

18 + 5b = 33

5b = 33 - 18

5b = 15

b = 3.