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17 August, 05:46

Solve for z, and give your answer in the form a + bi

(conj) z+2z = 2+4i+conj (7+3i)

**conj refers to conjugate of a complex number

(a line on top of it)

+1
Answers (1)
  1. 17 August, 05:56
    0
    The answer is z = 3 + i

    z = a + bi

    conj (z) = a - bi

    conj (7 + 3i) = 7 - 3i

    (conj) z + 2z = 2 + 4i + conj (7 + 3i)

    a - bi + 2 (a + bi) = 2 + 4i + 7 - 3i

    a - bi + 2a + 2bi = 2 + 4i + 7 - 3i

    3a + bi = 9 + i

    From here:

    3a = 9 and bi = i

    a = 9/3 b = i/i

    a = 3 b = 1

    z = a + bi

    z = 3 + 1 * i

    z = 3 + i
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