The riverside geyser in Yellowstone erupts about every 6.25 h. When the geyser erupts, the water has an initial upward velocity of 69 ft / s. What is maximum height of the geyser?

Correct answer: Hmax = 22.11 m

Step-by-step explanation:

The subject of this problem is a vertical shot upwards, to which the following formula applies:

V₀² - V² = 2 · g · H where is:

V₀ - initial velocity

V - final velocity

g = 10 m/s²

H - final height

Given:

V₀ = 69 ft/s = 21.03 m/s

V = 0 m/s

Hmax = ?

V₀² = 2 · g · Hmax ⇒ Hmax = V₀² / 2 · g

Hmax = 21.03² / 2 · 10 = 442.26 / 20 = 22.11 m

Hmax = 22.11 m

God is with you!