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24 January, 21:48

Melanie invested 5,500 in an account paying an interest rate of 6.9% compounded continuously. How much money to the nearest dollar would be in the account after 11 years

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  1. 25 January, 01:03
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    Correct answer: AV = 11,748 $

    Step-by-step explanation:

    Given:

    I = 5,500$

    n = 11 years

    p = 6.9 % = 0.069

    where is:

    AV - accumulated value

    I - investment

    p - interest

    n - number of years as the accounting period

    Accumulated value of an investment continuously compounded is calculated with next formula:

    AV = I · eⁿᵇ where is:

    n - number of years as the accounting period

    b = p = 6.9% = 0.069

    n · b = 11 · 0.069 = 0.759

    AV = 5,500 · e⁰⁷⁵⁹ = 5,500 · 2.7183⁰⁷⁵⁹ = 5,500 · 2.136 = 11,748 $

    AV = 11,748 $

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