A rectangle has a length that is three feet more than twice it's width. If the area of the rectangle is 90 square feet, then algebraically determines its width and length

Answer: width = 6 feet

Length = 15 feet

Step-by-step explanation:

Let L represent the length of the rectangle.

Let W represent the width of the rectangle.

A rectangle has a length that is three feet more than twice its width. It means that

L = 2W + 3

Area = length * width

If the area of the rectangle is 90 square feet, it means that

W (2W + 3) = 90

2W² + 3W = 90

2W² + 3W - 90 = 0

2W² + 15W - 12W - 90 = 0

W (2W + 15) - 6 (2W + 15) = 0

W - 6 = 0 or 2W + 15 = 0

W = 6 or W = - 15/2

Since the width cannot be negative, then

W = 6

L = 2W + 3 = 2 * 6 + 3

L = 15