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18 August, 20:03

Find the sum. 0+3+6 + ... + (3n-3)

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  1. 18 August, 22:32
    0
    Step-by-step explanation:

    a1 = 0

    an = a1 + (n - 1) * d = 3n - 3

    a1 = 0

    (n - 1) * d = 3 (n-1)

    From which d = 3

    Now for the sum

    Sum = (a1 + an) * n/2

    Sum = (an * n) / 2

    Sum = 3 (n - 1) * n / 2

    Sum = (3n - 3) * n/2

    Sum = (3n^2 - 3n) / 2
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