A lot of 1115 components contains 275 that are defective. Two components are drawn at random and tested. Let A be the event that the first component drawn is defective, and let B be the event that the second component dràwn is defective.

1) Find P (A).

2) Find P (BIA).

3) Find P (AnB)

1) P (A) = 0.2466

2) P (B|A) = 0.246

3) P (AnB) = 0.0607

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

1) Find P (A).

This is the probability that the first component is defective.

1115 components, of which 275 are defective. So

P (A) = 275/1115 = 0.2466

2) Find P (BIA).

This is the probability that the second component is defective, given that the first is.

Now there are 1114 components, of which 274 are defective. So

P (BIA) = 274/1114 = 0.246

P (B|A) = 0.246

3) Find P (AnB)

P (AnB) = P (A) * P (BIA) = 0.2466*0.246 = 0.0607

P (AnB) = 0.0607