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9 February, 11:21

A polynomial function has roots - 5 and 1. Which of the following could represent this function?

(x) = (x + 5) (x + 1)

f (x) = (x - 5) (x - 1)

f (x) = (x - 5) (x + 1)

f (x) = (x + 5) (x - 1)

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Answers (2)
  1. 9 February, 11:48
    0
    Te that's is a function
  2. 9 February, 13:09
    0
    Option D is correct. i. e., f (x) = (x + 5) (x - 1)

    Step-by-step explanation:

    Given: Roots of Polynomial are - 5 and 1

    To find: Polynomial function

    We substitute given value of roots in each polynomial and check

    if for both value polynomial given 0 then that our required polynomial

    A). f (x) = (x + 5) (x + 1)

    for x = - 5

    f (-5) = (-5 + 5) (-5 + 1)

    = 0 * (-4) = 0

    for x = 1

    f (1) = (1 + 5) (1 + 1)

    = 6 * 2 = 12 ≠ 0

    Thus, It is not required polynomial

    B). f (x) = (x - 5) (x - 1)

    for x = - 5

    f (-5) = (-5 - 5) (-5 - 1)

    = - 10 * (-6) = 60 ≠ 0

    for x = 1

    f (1) = (1 - 5) (1 - 1)

    = - 4 * 0 = 0

    Thus, It is not required polynomial

    C). f (x) = (x - 5) (x + 1)

    for x = - 5

    f (-5) = (-5 - 5) (-5 + 1)

    = - 10 * (-4) = 40 ≠ 0

    for x = 1

    f (1) = (1 - 5) (1 + 1)

    = - 4 * 2 = - 8 ≠ 0

    Thus, It is not required polynomial

    D). f (x) = (x + 5) (x - 1)

    for x = - 5

    f (-5) = (-5 + 5) (-5 - 1)

    = 0 * (-6) = 0

    for x = 1

    f (1) = (1 + 5) (1 - 1)

    = 6 * 0 = 0

    Thus, It is required polynomial

    Therefore, Option D is correct. i. e., f (x) = (x + 5) (x - 1)
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