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3 August, 08:04

If a circle has a radius of / sqrt{13}

and is centered at (9, - 3), what is the equation of this circle?

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  1. 3 August, 08:28
    0
    (x-9) ^2 + (y+3) ^2 = 13

    Step-by-step explanation:

    The equation of a circle can be written as

    (x-h) ^2 + (y-k) ^2 = r^2

    Where (h, k) is the center and r is the radius

    (x-9) ^2 + (y--3) ^2 = (sqrt (13)) ^2

    (x-9) ^2 + (y+3) ^2 = 13
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