The difference of two negative integers is 8 and their product is 48. Find the two integers.

Question

Mathematics

Azaria Hampton

9 July, 14:38

The difference of two negative integers is 8 and their product is 48. Find the two integers.

+3

Answers (1)

Know the Answer?

Carly Long · Answer 1

The answer is 12 and 4

Step-by-step explanation:

1st equation: - x - (-y) = 8

2nd equation: (-x) (-y) = 48

-x - (y) = 8

-x+y+8

y=x+8

-x (x+8) = 48

-x^2-8x=48

Multiply - 1

x^2+8x=-48

x^2+8x+48=0

(x+12) (x-4) = 0

x=-12

x=4

Check:

- (-12) - (4) = 8

12-8=8

8=8

(-12) (-4) = 48

48=48