The Flat Rock auto assembly plant in Detroit, Michigan, produces three different makes of automobiles. In two years, the plant constructed a total of 390,000 cars. If 90,000 more cars were made in the first year than in the second year, how many cars were made in each year?

a. first year: 90,000

second year: 180,000

b. first year: 300,000

second year: 90,000

c. first year: 240,000

second year: 150,000

d. first year: 180,000

second year: 90,000

Question

Mathematics

Bernard Harper

2 January, 19:19

The Flat Rock auto assembly plant in Detroit, Michigan, produces three different makes of automobiles. In two years, the plant constructed a total of 390,000 cars. If 90,000 more cars were made in the first year than in the second year, how many cars were made in each year?

a. first year: 90,000

second year: 180,000

b. first year: 300,000

second year: 90,000

c. first year: 240,000

second year: 150,000

d. first year: 180,000

second year: 90,000

+2

Answers (2)

Know the Answer?

Keira Chavez · Answer 1

c. first year: 240,000

second year: 150,000

Step-by-step explanation:

We let the number of cars made in the second year be X. Consequently, the number of cars made in the first year would be X+90000 since we are told that 90,000 more cars were made in the first year than in the second year. Furthermore, we are also told that the total number of cars constructed in these two years is 390,000, implying that;

X+X+90000=390000

2X+90000=390000

2X=390000-90000

2X=300000

X=150000; number of cars made in second year

The number made in the first year is thus;

150000+90000 = 240000

Kayden Richmond · Answer 2

Option c is correct

So, the cars made in 1st year = x = 240,000

and the cars made in 2nd year = 150,000

Step-by-step explanation:

in this question we have to find the number of cars made in each year by The Flat Rock auto assembly plant.

Given:

the plant constructed a total of 390,000 cars and 90,000 more cars were made in the first year than in the second year

Let cars made in 1st year = x

and cars made in 2nd year = y

then the plant constructed a total of 390,000 will be:

x + y = 390,000 (i)

and

90,000 more cars were made in the first year than in the second year can be written as:

x=90,000 + y (ii)

Solving equation (i) and (ii) we can find the values of x and y

Putting value of x from eq (ii) into eq (i)

(90,000 + y) + y = 390,000

90,000 + y + y = 390,000

2y = 390,000 - 90,000

2y = 300,000

y = 150,000

Putting value of y in equation (ii) we can find the value of x

x = 90,000 + y

x = 90,000 + 150,000

x = 240,000

So, the cars made in 1st year = x = 240,000

and the cars made in 2nd year = 150,000.