Ask Question
7 November, 00:10

Order the steps to solve the equation log3 (x + 2) = log3 (2x2 - 1) from 1 to 6. 0 = (2x - 3) (x + 1)

0 = 2x2 - x - 3

Potential solutions are - 1 and 3

2

.

2x - 3 = 0 or x + 1 = 0

x + 2 = 2x2 - 1

3log3 (x + 2) = 3log3 (2x2 - 1)

+4
Answers (2)
  1. 7 November, 00:54
    0
    Step 1

    log3 (x + 2) = log3 (2x² - 1)

    Step 2

    x + 2 = 2x² - 1

    Step 3

    2x² - x - 3 = 0

    Step 4

    (2x - 3) (x + 1) = 0

    Step 5

    2x - 3 = 0 or x + 1 = 0

    Step 6:

    Potential solutions are - 1 and 3/2

    Step-by-step explanation:

    Step 1

    log3 (x + 2) = log3 (2x² - 1)

    Step 2

    x + 2 = 2x² - 1

    Step 3

    2x² - x - 3 = 0

    Step 4

    2x² - 3x + 2x - 3 = 0

    x (2x - 3) + 1 (2x - 3) = 0

    (2x - 3) (x + 1) = 0

    Step 5

    2x - 3 = 0 or x + 1 = 0

    Step 6:

    x = 3/2 or x = - 1

    Potential solutions are - 1 and 3/2
  2. 7 November, 02:32
    0
    in short 4, 3, 6, 5, 2,1
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Order the steps to solve the equation log3 (x + 2) = log3 (2x2 - 1) from 1 to 6. 0 = (2x - 3) (x + 1) 0 = 2x2 - x - 3 Potential solutions ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers