What is the equation of the line that passes through (5,1 with slope being - 3?

A. Y+1=3x (x+5)

B. Y-1=3 (x-5)

C. Y-1=-3 (x-5)

D. Y+1=-3x (x-5)

Correct Answer: C

y = mx + c

m is the slope and c is the y-intercept

now, y = - 3x + c (because slope is - 3)

as the line passes through (5,1), these values must satisfy the above equation:

So, 1 = - 3 (5) + c

c = 1 + 15 = 1 6

so, equation:

y = - 3x + 16

y = - 3x + 15 + 1

y-1 = - 3 (x - 5)