The height of a triangle is 8 centimeters greater than half its base. The area of the triangle is 48 square centimeters what is the base length of the triangle

base = 8 cm

height = 12 cm

Step-by-step explanation:

We will need the formula for area of a trianlge, which is

A = (1/2) bh where b is the base, and h is the height

We are given two formulas ...

"The height of a triangle is 8 centimeters greater than half its base" becomes

h = (1/2) b + 8

"The area of the triangle is 48 square centimeters" becomes

48 = (1/2) bh

Plug the first formula into the second to solve for h

48 = (1/2) b[ (1/2) + 8] (h becomes (1/2) b + 8)

Now solve for b

48 = (1/4) b² + 4b

**This is a quadratic euquation. Solve using factoring ...

(1/4) b² + 4b - 48 = 0 (subtract 48 from both sides)

b² + 16b - 192 = 0 (multiply by 4 so b² is by itself, it's easier to factor this way)

Now factor ...

(b + 24) (b - 8) = 0 (you need two numbers that add to 16 and multiply to - 192)

Set each binomial equal to zero and solve for b

b + 24 = 0

b = - 24

**this anwser is not valid because b is a length, and you can't have negative length

b - 8 = 0

b = 8

Since the other solution is invalid, the base is b

If the base is b, then the height is ...

h = (1/2) b + 8

h = (1/2) (8) + 8

h = 4 + 8

h = 12