Scores of each of the previous calculus tests were normally distributed with a mean of 74 and standard deviation of 3.8. Steve will be taking the test tomorrow. What is the P (z<-1.05) ?

-2.2 (-2.2124%) is the answer as - 2.2124^2 = - 4.89% is found first below. - 2.2124 is part of the derivation equation to find the relation with z.

z<-1.05 therefore = - 2.2<-1.05

Step-by-step explanation:

-4.89%

-0.27631578947 x 74 = - 20.4473684208

P) z<-105) = 100/-20.4473684208 = - 4.89060489067 less than the population of 100%

0 = population standard deviation = 3.8 we divide from 1.05

(in normal derivation questions we can multiply before dividing 0 key letter = (z - u) ^2 / divide all by N) This is why we divided.

N = the size of the population = 100/D we used 100/D to find the first part.

z = each value from the population = z<-1.05

u = the population mean = 74 we multiplied second step after first step 3.8 we divide from 1.05

So that 1.05/3.8 = - 0.27631578947 x 74 = D

We then Divide into N = 100/D

to find a whole or a percentage.

= - 4.89

z = - 2.2