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26 April, 16:11

A halloween assorted bag of candy contains 4 Snickers, 2 packages of M&M's, & 3 Butterfingers. What is the probability of selecting some M&M's, putting them back, and then selecting a Butterfinger?

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  1. 26 April, 19:29
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    2/27

    Step-by-step explanation:

    In the question we have:

    4 snickers

    2 packages of M&M's

    3 Butterfingers.

    Total number of candies in the Halloween bag = 9

    Probability of selecting some M&M's and putting them back = 2/9

    Probability of selecting a Butter finger = 3/9

    Therefore, the probability of selecting some M&M's, putting them back, and then selecting a Butterfinger =

    Probability of selecting some M&M's and putting them back * Probability of selecting a Butter finger

    2/9 * 3/9

    = 6 / 81

    = 2/27
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