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20 October, 07:07

Find each measure for the given set of dа ta:

11, 13, 17, 20, 22, 25, 27, 31, 31, 33

Mean =

Median =

Range =

Interquartile range =

+3
Answers (2)
  1. 20 October, 09:35
    0
    Mean = 23

    Median = 23.5

    Range = 22

    Interquartile range = 14
  2. 20 October, 10:49
    0
    Mean = 23

    Median = 23.5

    Range = 22

    Interquartile range = 15

    Step-by-step explanation:

    The mean of a set of numbers is the ratio of the total of these numbers to the number of numbers added. As such where there are u numbers and the sum of these numbers is P, the mean is

    = P/u

    Hence the mean of the numbers given

    = (11 + 13 + 17 + 20 + 22 + 25 + 27 + 31 + 31 + 33) / 10

    = 230/10

    = 23

    The median is the number at the middle after arranging from highest to lowest or vice versa

    = (22 + 25) / 2

    = 47/2

    = 23.5

    The range is the difference between the highest and lowest numbers

    = 33 - 11

    = 22

    the interquartile range

    = Q₃ - Q₁

    where Q₃ is the 3 (n + 1) / 4 placed observation

    Q₁ is the (n + 1) / 4 placed observation

    Q₃ = 3 (10 + 1) / 4

    = 8.25th

    = 31 + 0.25 (31 - 31)

    = 31

    Q₁ = (10 + 1) / 4

    = 2.75th

    = 13 + 0.75 (17 - 13)

    = 16

    Interquartile range

    = 31 - 16

    = 15
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