Find the cube roots of 8. Write the answer in a + bi form.

z = 2, - 1 + sqrt (3) i, - 1 + sqrt (3) i

Step-by-step explanation:

z³ = 8[cos (0) + isin (0) ]

z = 8^⅓ = 2

z = {8[cos (2pi) + isin (2pi) ]}^⅓

z = 2[cos (2pi/3) + isin (2pi/3) ]

z = - 1 + sqrt (3) i

z = {8[cos (4pi) + isin (4pi) ]}^⅓

z = 2[cos (4pi/3) + isin (4pi/3) ]

z = - 1 - sqrt (3) i

The answer is D