Solve for x if 2 (5x + 2) 2 = 48. x = StartFraction negative 2 + 2 StartRoot 24 EndRoot Over 5 EndFraction and x = StartFraction negative 2 minus 2 StartRoot 24 EndRoot Over 5 EndFraction x = StartFraction negative 2 + 2 StartRoot 24 EndRoot Over 2 EndFraction and x = StartFraction negative 2 minus 2 StartRoot 24 EndRoot Over 2 EndFraction x = StartFraction negative 2 + 2 StartRoot 6 EndRoot Over 5 EndFraction and x = StartFraction negative 2 minus 2 StartRoot 6 EndRoot Over 5 EndFraction x = StartFraction negative 2 + 2 StartRoot 6 EndRoot Over 2 EndFraction and x = StartFraction negative 2 minus 2 StartRoot 6 EndRoot Over 2 EndFraction
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Home » Mathematics » Solve for x if 2 (5x + 2) 2 = 48. x = StartFraction negative 2 + 2 StartRoot 24 EndRoot Over 5 EndFraction and x = StartFraction negative 2 minus 2 StartRoot 24 EndRoot Over 5 EndFraction x =