According tp the fundamental theorem of algebra, how many zeros does the polynomial below have? f (x) = x^3-10x^2+27x-12

The answer is 3.

The fundamental theorem of algebra says that a number of zeros of a polynomial are equal to the highest exponent on a variable.

The polynomial is f (x) = x ³ - 10x ² + 27x-12

The highest exponent of a variable x is 3: x ³

Therefore, the number of zeroes of the polynomial is 3.