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28 October, 11:40

Over two summers, Ray saved $800.00 and $600.00. The polynomial represents his savings at the beginning of the third year, where x is the growth factor. (The interest rate r is x - 1.) What is the interest rate he needs to save $1,650.00 after the third summer?

800x2 + 600x

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  1. 28 October, 14:27
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    So at the end of the third year, it would be 800 x^3 + 600x^2? And he doesn't work the third summer? Then 800x^3 + 600x^2 = 1650 x = 1.0657758228 ... so he needs an interest rate of 6.57758 ... % compounded annually.
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