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28 March, 14:19

When 200 gallons of oil were removed from a tank, the volume of oil left in the tank was 3/7 of the tank's capacity. what was the tank's capacity? (1) before the 200 gallons were removed, the volume of oil in the tank was 1/2 of the tank's capacity?

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  1. 28 March, 14:48
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    Step-by-step explanation:

    "When 200 gallons of oil were removed from a tank" algebraically looks like this:

    V - 200.

    " ... the volume of oil left in the tank was 3/7 of the tank's capacity" algebraically looks like this:

    3/7 (V)

    Therefore, the equation is

    V - 200 = 3/7 (V)

    Begin by multiplying both sides by 7:

    7 (V - 200) = 3V and

    7V - 1400 = 3V so

    -1400 = - 4V so

    V = 350 gallons

    That's if the volume of the oil in the tank was 3/7 of the tank's capacity.

    For the other part of the problem, we set up the equation almost the same, except the 3/7 is a 1/2:

    V - 200 = 1/2 (V)

    Multiplying both sides by 2 gives you

    2 (V - 200) = V and

    2V - 400 = V so

    -400 = - V so

    V = 400
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