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9 September, 13:40

A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 22 subjects had a mean wake time of 105.0 min. After treatment, the 22 subjects had a mean wake time of 95.7 min and a standard deviation of 22.2 min. Assume that the 22 sample values appear to be from a normally distributed population and construct a 99 % confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 105.0 min before the treatment? Does the drug appear to be effective?

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  1. 9 September, 14:12
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    Step-by-step explanation:

    We want to determine a 99% confidence interval estimate of the mean wake time for a population with drug treatments.

    Number of sample, n = 22

    Mean, u = 95.7 min

    Standard deviation, s = 22.2 min

    For a confidence level of 90%, the corresponding z value is 2.58.

    We will apply the formula

    Confidence interval

    = mean ± z * standard deviation/√n

    It becomes

    95.7 ± 2.58 * 22.2/√22

    = 95.7 ± 12.21

    The lower end of the confidence interval is 95.7 - 12.21 = 83.49 min

    The upper end of the confidence interval is 95.7 + 12.21 = 107.91 min

    The result suggests that there is no significant difference between the mean wake time before and after treatment. Therefore, the drug does not appear to be effective.
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