1. 2 (H-8) - h=h-16

A. H=8

B. H=-8

C. H = infinitely many solution

D. H = no solution

2. 3+6Z=13+6z

A. Z = - 5/6

B. Z = 2 2/3

C. Z=infinitely many solutions

D. Z=no solution

(1) C and (2) D

(1)

distribute the left side of the equation

2h - 16 - h = h - 16 (simplify left side)

h - 16 = h - 16

Since both sides are equal, any value of h will make the equation true.

Hence there are infinitely many solutions to the equation → C

(2)

3 + 6z = 13 + 6z (subtract 6z from both sides)

3 = 13 ← not possible

Hence there are no solutions to the equation → D