three positive whole numbers have a sum of 48. The second number is 5 times the first and the third number is twice the second number. What are the three numbers?

3,15 and 30

Step-by-step explanation:

Let the number be A, B and C.

The sum of the three positive numbers are 48

That's

A + B + C = 48

The second number is 5 times the first

That's

B = 5A

The third number is twice the second

That's

C = 2 x 5A = 10A

We now have

A + B + C = 49

B = 5A

C = 10A

Now substitute 5A for B and 10A for C into the first equation

We have

A + B + C = 48

A + 5A + 10A = 48

16A = 48

Divide both sides by 16 to get A

16A/16 = 48/16

A = 3

Recall

B = 5A

So

B = 5 x 3

B = 15

Also,

C = 10A

Therefore

C = 10 x 3

C = 30

The numbers are 3,15 and 30

3, 15 and 30

Step-by-step explanation:

Let the first number be x

Second number is 5 times the first number = 5x

Third number is twice the second number = 2*5x = 10x

The equation becomes;

x + 5x + 10x = 48

16x = 48

x = 48 : 16

x = 3

Therefore the three numbers are x = 3, 5x = 15 and 10x = 30