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7 April, 09:02

An instructor gives a class a set of 10 problems and says that the nal exam will consist of a random selection of 5 of the problems. If a student has gured out how to solve 7 of the problems, what is the probability that he or she will answer at least 4 problems correctly?

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  1. 7 April, 12:29
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    probability that he or she will answer at least 4 problems correctly = 0.5

    Step-by-step explanation:

    probability that he or she will answer at least 4 problems correctly is given as;

    P (at least 4 correctly) = P (exactly 4 correctly) + P (all 5 correctly)

    Since there are 10 problems. 4 is from the 7 problems chosen and 1 is from the 3 problems we can't figure out. Thus, P (exactly 4 correctly) = 7C4 x 3C1

    Thus, P (at least 4 correctly) = [ (7C4) x (3C1) ] / (10C5) ] + [ (7C5) / (10C5) ]

    = [ (35 x3) / 252 ] + [21/252]

    = [ 105/252 ] + [ 21/252 ]

    = 126 / 252

    = 0.5
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