What is the coordinates of the vertex of y+10=4 (x-1) ^2

(1, - 10)

Step-by-step explanation:

Only the y can be on the left hand side. The square has been completed so all you need do is transfer the 10 to the right and read the x, y values for the vertex.

I have provided a graph to show you that the vertex and my answer are the same (hopefully).

y + 10 = 4 (x - 1) ^2 Subtract 10 from both sides.

y + 10-10=4 (x - 1) ^2 - 10 Combine

y = 4 (x - 1) ^2 - 10

Now we need to make the square term = 0

x - 1 = 0 Add 1 to both sides

x - 1 + 1 = 0 + 1 Combine

x = 1 When x = 1 the square term will equal 0.

The vertex should be (1, - 10)