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3 June, 20:24

In a survey sample of 83 respondents, about 30.1% of the sample work less than 40 hr per week. What is the estimated standard error of the proportion for this group?

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  1. 3 June, 21:46
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    Step-by-step explanation:

    The standard error for a proportion is √ (pq/n), where q=1-p.

    √ (0.301 * 0.699 / 83) ≈ 0.050
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