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4 November, 16:40

For what values of b the relation R:{ (b^2, 5), (5b, 6) } is not a function?

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  1. 4 November, 18:39
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    B=5,0.

    Step-by-step explanation:

    It's not that hard. It's just that it might throw you off a bit with the R and the other things. Functions if you don't remember are where the coordinates don't have the same x and y. So since the y1 and y2 are different then to make it not a function, you have to make x1 and x2. To make it that b would have to be = to 5 and 0.
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