What is the factored form of the expression?

d^2 - 14d + 49

d^2 - 14d + 49 = (d-7) (d-7).

Step-by-step explanation:

Given the expression is d^2 - 14d + 49.

d^2 - 14d + 49 = d^2 - 2*7*d + 7^2

We know the formula of square of difference as given below:-

x^2 - 2*x*y + y^2 = (x-y) ^2

Using the above formula in the problem, here x = d and y = 7.

d^2 - 2*7*d + 7^2 = (d-7) ^2

d^2 - 2*7*d + 7^2 = (d-7) (d-7)

So, d^2 - 14d + 49 = (d-7) (d-7).

(d-7) (d-7)

Step-by-step explanation:

We have to make factored form of the expression.

Given expression is:

d²-14d+49

Split the middle term to make the equation into two groups such that the sum of 2 numbers should be - 14 and their product be 49.

d²-7d-7d+49

Making two groups and taking the common term out:

d (d-7) - 7 (d-7)

Take (d-7) common

(d-7) (d-7) which is factored form of d²-14d+49.