What is the product of (3p-7) (2p²-3p-4)

A. 6p³+23p²+9p+28

B. 6p³-23p²-9p+28

C. 6p³-23p²+9p+28

D. 6p³+23p²-9p+28

Choice C is the correct answer.

Step-by-step explanation:

Given expression is

(3p-7) (2p²-3p-4)

we have to find the product of linear expression to quardatic expression.

Firstly, multiply 3p to quardatic expression and - 7 to quardatic expression and add.

3p (2p²-3p-4) - 7 (2p²-3p-4)

Multiply 3p to each term of quardatic expression and - 7 to each term of quardatic expression and add all terms:

3p (2p²) + 3p (-3p) + 3p (-4) - 7 (2p²) - 7 (-3p) - 7 (-4)

6p³-9p²-12p-14p²+21p+28

add like terms

6p³ + (-9-14) p²+p (-12+21) + 28

6p³-23p²+9p+28 which is the correct answer.