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Today, 17:38

A car is bought at the price of $20,000. The value decreases at the rate of. 20 every year (t). The exponential expression 20,000 (0.80) t describes this situation. Find the price of the car after 3 years.

Question 11 options:

A)

$9,399

B)

$11,874

C)

$10,240

D)

$5,892

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Answers (1)
  1. Today, 18:37
    0
    y = 20,000 (.80) ^t

    y = 20,000 (0.80) ^3

    0.8^3 = 0.512

    0.512 x 20,000 = 10240

    Your answer would be C. $10,240.
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